Vladimir Abstract A ball is tossed obliquely. The vectors of position and velocity are measured. The acceleration is calculated. Introduction A toy company is now making an instructional videotape on how to predict the position. Therefore, in order to make the prediction accurate, how the horizontal and vertical components of a ball’s position as it flies through the air should be understood.
This experiment is to calculate functions to represent the horizontal and arterial positions of a ball. It does so by measuring and calculating the components of the position and velocity of the ball during the toss. Therefore, we can also calculate the acceleration during the procedure. Prediction The x-axis is located on the ground level horizontally, pointing to where the ball is initially thrown, that is opposite the direction the ball flies.
The vertical y-axis passes through the highest point of the ball during the fly and point upward. Since the ball experiences no other force, except for gravity, during the toss. There is no horizontal force. It is predicted that the ball should have a constant horizontal speed, which is the horizontal component of initial velocity. Vertically, it has gravity pulling it down all the time. So it should have an acceleration of -g (minus is for the direction).
Since it has a vertical velocity, the ball should go up for a while and then fall down. The position graph should be a parabola. The function should be as follows: horizontal (x) vertical (y) acceleration (a)m/so -g velocity (v) vs. Ivy=WOO -g*t position (x) Xerox+x-you The Box and Boy are for the initial horizontal and vertical velocities and the ox and you re for the initial horizontal the vertical position. Procedure A 146. Egg spherical ball is thrown upward obliquely.
Its toss trajectories were recorded by a video camera. The Motion Lab analysis software was used to generate the graph of the position and velocity as functions of time both horizontally and vertically. The horizontal position and velocity versus time function were fit by eye as oblique line and horizontal line. The vertical x(t) and v(t) functions were parabola and oblique line. The acceleration should be the slope of the velocity of both components. Data Horizontal: Figurer : horizontal position change due to time
Figurer: horizontal velocity change due to time Vertical: Figurer: vertical position change due to time Figurer: vertical velocity change due to time Analysis The horizontal velocity versus time graph is a horizontal line, which means the velocity doesn’t change during the entire process, as is in the graph of position as a function of time, a straight line. Vs.=- 1. Mm/s Xx=(O. Mm)- (1. Mm/s)t The speed is constant, so the acceleration is mm/so. And the initial velocity is -1. Mm/s. The initial position is 0. Mm/ The vertical velocity is proportional to the time. Since it has an initial velocity.